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U+6y=32 u+3y=17 u=2 y=5 - Brainly.in

2023年10月3日 · Answer: \nu=2,y=5 Step-by-step explanation: We are given with 2 equations in terms of u and y that are \nu+6y=32 \nu+3y=17 On subtracting these 2 equations we get \nu+6y-u-3y=32-17 …

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9x+3y+12=0 18x+6y+24=0 - Brainly.in

18x + 6y + 24 = 0 If you observe both equations, you'll notice that the ratio of coefficients of x in both equations, coefficients of y in both equations and the constant terms in both equations are constant.